MAT/116 Week 3 dq 1

In week 3, Section 2.4 of the text discussed some mathematical formulas that are used in various fields to solve problems in geometry.Here’s a problem involving the circumference and radius of a circle. The equation for circumference C in terms of radius r is: C = 2pr.Let’s assume the earth is a perfect sphere and we tie a rope around the earth. The rope sits tightly on the surface (circumference) of the earth.Now let’s cut the rope and add 1 foot to it. (We’ve added 1 foot to the circumference.) The rope no longer sits tightly on the earth, but is now some distance away from the surface. Question: How far away from the surface is the rope after we’ve added the foot to the circumference?  Or asking another way– when I add 1 foot to the circumference, what happens to the radius? Show the equations and how they were used to solve this problem.( Note: No need to bring in the distance around the earth which is 25000 miles. Just work with the equation for circumference.)

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